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Question

If the points A(4, 3) and B(x, 5) lie on a circle with the centre O (2, 3), find the value of x.

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Solution

Given centre of circle is O(2, 3)
Points on the circle are A(4, 3) and B(x, 5)
OA =OB (Radius)
Recall the distance between two points formula
square root of open parentheses x subscript 2 minus x subscript 1 close parentheses squared plus open parentheses y subscript 2 minus y subscript 1 close parentheses squared end root
square root of open parentheses 4 minus 2 close parentheses squared plus open parentheses 3 minus 3 close parentheses squared end root equals square root of open parentheses x minus 2 close parentheses squared plus open parentheses 5 minus 3 close parentheses squared end root square root of 4 equals square root of open parentheses x minus 2 close parentheses squared plus open parentheses 5 minus 3 close parentheses squared end root
Squaring on both the sides, we get
4 equals open parentheses x minus 2 close parentheses squared plus 4 open parentheses x minus 2 close parentheses squared equals 0
Þ x – 2 = 0
∴ x = 2

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