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Question

If the polynomial (x+1)2015−x2015−1 is divided by (x+x2+x3), then the remainder is

A
x2x
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B
x2+x
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C
1
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D
0
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Solution

The correct option is D 0
Q(x+x2+x3)=x(1+x+x2)

[(x+1)2015x20151]=[x+x2+x3]q(x)+R(x)

Put x=0

R(x)=101=0

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