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Question

If the position vector of a particle is ^r=(3^i4^j) meter and its angular velocity is ¯ω=(^j2^k)rad/sec then its linear velocity is (in m/s)

A
(8^i+6^j+3^k)
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B
(3^i6^j+8^k)
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C
(3^i6^j+6^k)
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D
(6^i8^j+3^k)
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Solution

The correct option is A (8^i+6^j+3^k)
We have v=ω×r
or
v=∣ ∣ijk012340∣ ∣
or
v=(8i+6j+3k)

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