If the pressure and absolute temperature of $2$ liter of carbon dioxide are doubled, the volume of carbon dioxide would become (in litres)?

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Solution

The pressure and absolute temperature are doubled.
Therefore, $P_{2} = 2 P_{1}$ and $T_{2} = 2 T_{1}$ and $V_{1} = 2$ litre
now, $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
$\Rightarrow \frac{P_{1} \times 2 l i t}{T_{1}} = \frac{2 P_{1} \times V_{2}}{2 T_{1}}$
$\Rightarrow V_{2} = 2 l i t$
$∴$ The volume of carbon dioxide would not change i.e. $2 l i t$ .

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