If the pressure and absolute temperature of $2 l i t e r s$ of carbon dioxide are doubled the volume of the gas would be:

2 l i t r e s

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4 l i t r e s

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5 l i t r e s

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7 l i t r e s

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Solution

The correct option is A $2 l i t r e s$
$From ideal gas equation Given: P_{2} = 2P_{1}; T_{2} = 2T_{1} \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} \Rightarrow \frac{P_{1} (2)}{T_{1}} = \frac{(2 P_{1}) (V_{2})}{2 T_{1}} \Rightarrow V_{2} = 2 l i t r e s$

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