If the prime factorization of a natural number n is 23- 32- 52- 7- write the number of consecutive zeros in n -

Since, it is given that nbsp; Hence the number of consecutive zeroes are. ...

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If the prime factorization of a natural number n is 2³ ✕ 3² ✕ 5² ✕ 7, write the number of consecutive zeros in n.

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If the prime factorisation of a natural number n is 2⁴× 3⁴ × 5³ × 7, then the number of consecutive zeros in n, is _________.

N = 2^{3} \times 3^{2} \times 5^{3} \times 10.

2 P + 1

N = 2^{3} \times 3^{2} \times 5^{3}

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