If the probability distribution of a random variable x is
$X = x_{1} : - 2 - 10123$
$p (X = x_{1}) : 0.1 k 0.2 2 k 0.3 k$ then the mean of x is

0.6

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0.8

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1.0

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0.3

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Solution

The correct option is B $0.8$
$\sum_{i = - 2}^{3} p_{i} = 1 0.1 + k + 0.2 + 2 k + 0.3 + k = 1 4 k = 1 - 0.6 = 0.4 k = 0.1 M e a n = \sum_{i = - 2}^{3} x_{i} p_{i} = - 0.2 - k + 2 k + 0.6 + 3 k = 4 k + 0.4 = 0.4 + 0.4 = 0.8$

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