if the product of 2 zeroes of a polynomial f(x)=2x^3 + 6x^2 -4x + 9 =3 then its 3 zero is pls expln with steps

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Solution

for a cubic polynomial of the form: Ax^3 + Bx^2+ Cx+D
product of roots= -D/A
so for the given equation: D=9, A=2
product of roots = -9/2
given product of 2 roots=3
let the third root be R, then,
R*3=-9/2
=>R=(-9/2)/3
=>R=-3/2
So third root= -3/2

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