If the quantity of metal in a metallic oxide is 60% then its equivalent weight is:

\frac{1}{5}

of molecular weight

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2}

of molecular weight

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{3}{2}

of molecular weight

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3}{5}

of molecular weight

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{1}{2}$ of molecular weight
If the atomic weight of the metal is 'a', then $\frac{a}{a + 16} = \frac{60}{100}$
$a = 24$
This shows that the metal is magnesuim.
Equivalent weight of the oxide
$= \frac{M o l e c u l a r w e i g h t}{C h a r g e o n c a t i o n}$
$= \frac{M o l e c u l a r w e i g h t}{2}$

Suggest Corrections

Similar questions

12

H_{3} P O_{2} = \frac{m o l e c u l a r w e i g h t}{1}

H_{3} P O_{3} = \frac{m o l e c u l a r w e i g h t}{2}

H_{3} P O_{4} = \frac{m o l e c u l a r w e i g h t}{3}

If equivalent weight of a trivalent metal is 32.7. The molecular weight of its chloride is :

37.2

W

Join BYJU'S Learning Program