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Question

If the radius of a 2713Al nucleus is estimated to be 3.6 fermi, find the radius of a 12552Te nucleus.

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Solution

Radius of 2713Al=3.6fermi=3.6×1013m
Mass number of 2313Al=27
Using radius, Moc-number formula,
R=R(A)13=3.6×1013=(27)13RR=1.2×1013m
Now, for 12332Te, radius is given by,
R=R(A)12=1.2×1013×(123)13=6×1013m
Radius of 12332Tenucleus=6fermi


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