wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the radius of second Bohr's orbit of hydrogen atom is r2 then the radius of third Bohr's orbit of Be3+ ion will be:

A
9r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9r28
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
9r216
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
9r24
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 9r216
Bohr's radius for nth orbit, (rn)=0.529[n2Z]A
where n=Orbit number, Z=Atomic number
(rn)=r2 for 2nd orbit of hydrogen

Therefore, ratio of both the radius gives:
rHrBe3+=n2HZH×ZBe3+n2Be3+=22×41×32

r2rBe3+=169

rBe3+=9r216

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon