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Floating and Sinking

If the radius...

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If the radius of the soap bubble is r,its volume V and excess pressure inside it is P then 1/PV is how proportional to r

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Q. If the excess pressure inside a soap bubble of radius

r_{1}

in air is equal to the excess pressure inside air bubble of radius

r_{2}

inside the soap solution, then

r_{1} : r_{2}

Q. The excess of pressure inside a soap bubble is twice the excess pressure inside a soap bubble. The volume of the first bubble is n times the volume of the second where n is

Q. The excess pressure inside a soap bubbles is twice the excess pressure inside a second soap bubble. the volume of the first bubble is

n

times the volume of the second bubble where

n

Q. The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is
(a) 4
(b) 2
(c) 1
(d) 0.125

Q. Assertion :When a large soap bubble and a small soap bubble are connected by a capillary tube the large bubble expands while the small bubble shrinks. Reason: The excess pressure inside a bubble is inversely proportional to radius and air flows from small bubble to large bubble.

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