Question

If the ratio of the areas of two squares is 9 : 1, find the ratio of their perimeters.

Answer 1

Let their sides be $s_1,s_2$

As we know that

Area of square with side $s$ is $s^2$

Given ratio of areas of two squares is $9:1$

$⟹s_1^2:s_2^2=9:1$

$⟹\frac{s_1}{s_2}=3$

As we know that

Perimeter of square with side $s$ is $4s$

Ratio of their perimeters is $4s_1:4s_2=\frac{s_1}{s_2}=3$