The correct option is
A BlR2(v1r2−v2r1)R1R2(r1+r2)+r2r1(R1+R2)As the conducting rods are moving in magnetic field with velocity
v in opposite direction, thus an
EMF is induced in each rod according to the Lenz law.
EMF induced in rod MN E1=Bv1l .........(a)
EMF induced in rod M′N′ E2=Bv2l .......(b)
Combining the EMFs of the two rods, 1req=1r1+1r2 ⟹req=r1r2r1+r2 .......(1)
Also equivalent EMF Eeq=E2r2req−E1r1req
Putting the values and on solving we get, Eeq=E2r1−E1r2r1+r2 ............(2)
From Kirchhoff current law i=i1+i2
Using Nodal analysis Eeq−Vreq=V−0R1+V−0R2
⟹V=EeqreqR1R2req[(R1+R2)req+R1R2] .............(3)
∴ i1=VR1
From (1), (2) and (3), we get i1= (E2r1−E1r2)r1r2R2r1r2[(R1+R2)r1r2+(r1+r2)R1R2]
Using (a) and (b), ⟹|i1|= |v2r1−v1r2|BlR2[(R1+R2)r1r2+(r1+r2)R1R2]