If the roots of the equation a\({x}^{2}\) + bx + c = 0 are reciprocal to each other, then :
a + c = 0
b = 0
a - c = 0
None
Let α,β be the roots of the equation
Given α =1β
αβ= 1
ca=1
c=a
c-a=0
If a root of the equation ax2+bx+c=0 be reciprocal of the equation then a′x2+b′x+c′=0, then