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Question

If the roots of the equation ax2+bx+c=0 be k+1k and k+2k+1, then (a+b+c)2=

A
b24ac
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B
c24ab
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C
b24ab
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D
None
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Solution

The correct option is A b24ac
k+1k+k+2k+1=ba ....(1)
And k+2k=cak=2aca
k+2k=cak=2aca ....(2)
Substitute the value of k from (2) in (1) c+a2a+2cc+a=ba
a(c+a)2+4a2c=2abc2a2b
(c+a)2+4ac=2bc2ab
(a+b+c)2=b24ac

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