If the roots of the equation $x^{2} - b x + c = 0$ are two consecutive integers, then what is the value of $b^{2} - 4 c$ ?

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Solution

The correct option is D
According to the question,
${\frac{(b - \sqrt{(b^{2} - 4 c)}}{2}} + 1 = (\frac{(b + \sqrt{(b^{2} - 4 c)})}{2})$
$((b - \sqrt{(b^{2} - 4 c)}) + 2 = ((b + \sqrt{(b^{2} - 4 c)})$
$\sqrt{(b^{2} - 4 c)} = 1$
$(b^{2} - 4 c) = 1$

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