If the roots of the quadratic equation ax2+bx+c=0 are non real, then for all values of a,b,c and x∈R, the expression a2x2+abx+ac is
A
positive
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B
non-negative
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C
negative
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D
may be positive, zero and negative
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Solution
The correct option is A positive Roots of the quadratic equation ax2+bx+c=0 are non real. ⇒b2−4ac<0 -----(1) Now, for the expression a2x2+abx+ac, Δ=a2b2−4a3c=a2(b2−4ac)<0 from (1) Since, discriminant value is less than zero, coefficient of x2 and expression always have same sign. ∴a2x2+abx+ac>0 Hence, option A.