If the salts, $M_{2} X$ , $Q Y_{2}$ and $P Z_{3}$ have same solubilities (<<<1) , their $K_{s p}$ values are related as:

M_{2} X > Q Y_{2} > P Z_{3}

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M_{2} X < Q Y_{2} > P Z_{3}

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M_{2} X = Q Y_{2} > P Z_{3}

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M_{2} X = Q Y_{2} = P Z_{3}

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Solution

The correct option is B $M_{2} X = Q Y_{2} > P Z_{3}$ .
Let $S$ be the solubility in moles/litre.

The expression for the solubility product of $M_{2} X$ is $(2 S)^{2} S = 4 S^{3}$

The expression for the solubility product of $Q Y_{2}$ is $S (2 S)^{2} = 4 S^{3}$

The expression for the solubility product of $P Z_{3}$ is $S (3 S)^{3} = 27 S^{4}$

Since $S <<< 1$ , $M_{2} X = Q Y_{2} > P Z_{3}$ .

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