If the solubility of lithium sodium hexafluoride aluminate, $L i_{3} N a_{3} (A l F_{6})_{2}$ is $^{'} s^{'}$ mol/L, its solubility product is equal to :

729 s^{8}

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18 s^{3}

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3900 s^{8}

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2916 s^{8}

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Solution

The correct option is D $2916 s^{8}$
Solubility product is the maximum product of the ionic concentrations or activities of an electrolyte.
$\begin{matrix} L i_{3} N a_{3} (A l F_{6})_{2} \to 3 L i^{+} + 3 N a^{+} + 2 [A l F_{6}]^{3 -} 3 s 3 s 2 s \end{matrix}$
$K_{s p} = (3 s)^{3} (3 s)^{3} (2 s^{2}) = 2916 s^{8}$

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Solubility Product

Standard XIII Chemistry

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If the solubility of lithium sodium hexafluoride aluminate, Li3Na3(AlF6)2 is ′s′ mol/L, its solubility product is equal to :

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