Question

If the solution of $CuS{O}_4$ in which copper rod is immersed is diluted to 10 times, the electrode potential:

• A. increases by 0.295 V
• B. decreases by 0.0295 V
• C. increases by 0.059 V
• D. decreases by 0.059

Answer 1

The correct option is B decreases by 0.0295 V

If solution is diluted to 10 times , molar conc. $C{u}^{2+}$ is reduced to obe tenth of its original value

Nernst equation for: $C{u}^{2+}+2e^{-}\to Cu$ is

$E=E^O+\frac{0.059}{2}log\left[C{u}^{2+}\right]$ --------- (1)

By decreasing the conc. of $C{u}^{2+}$ by 1/10 times

E will decrease by 0.059/2V = 0.0295 V