Question

If the specific heat of lead is 0.03 $\frac{cal}{g^{\circ }C}$ , thermal capacity of $500$g of lead is.

• A. $5$cal ${}^o{C}^{-1}$
• B. $10$cal ${}^o{C}^{-1}$
• C. $15$cal ${}^o{C}^{-1}$
• D. $20$cal ${}^o{C}^{-1}$

Answer 1

The correct option is C $15$cal ${}^o{C}^{-1}$

If the specific heat of lead is $0.03cal/\left(g^{\circ }C\right)$ , thermal capacity of 500g of lead is.

Thermal capacity =mass*specific heat=$0.03\ast 500=15ca{l}^o{C}^{-1}$