If the specific resistance of a solution of concentration $C g$ equivalent $l i t r e^{- 1}$ is $R$ , then its equivalent conductance is :

\frac{100 R}{C}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{R C}{1000}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1000}{R C}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{C}{1000 R}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{1000}{R C}$
Equivalent conductance= $\frac{S p e c i f i c c o n d u c t a n c e \times 1000}{C o n c e n t r a t i o n}$
$= \frac{K \times 1000}{C o n c e n t r a t i o n}$
$ρ = R$ (given)
$\Rightarrow ρ = \frac{1}{K}$
$\Rightarrow R = \frac{1}{K}$
$\Rightarrow K = \frac{1}{R}$
Equivalent conductance= $\frac{1000}{R C}$

Suggest Corrections

Similar questions

H_{2} S O_{4}

1.3 \times 10^{2} {ohm}^{- 1} {cm}^{2} {eq}^{- 1}

26 \times 10^{- 2} {ohm}^{- 1} {cm}^{- 1}

H_{2} S O_{4}

0.01 M

K C l

0.0014 o h m^{- 1} c m^{- 1}

25^{\circ} C

(\land_{m}) = (\frac{k \times 1000}{M}) o h m^{- 1} c m^{2} m o l e^{- 1}

B a C l_{2}

c m^{3}

o h m^{- 1} c m^{- 1}

Join BYJU'S Learning Program