If the straight line, $2 x - 3 y + 17 = 0$ is perpendicular to the line passing through the points $(7, 17)$ and $(15, β),$ then $β$ equals :-

- 5

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- \frac{35}{3}

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\frac{35}{3}

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5

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Solution

The correct option is C $5$
Slope of given line is $\frac{2}{3}$

Lines are perpendicular so

$\frac{17 - β}{- 8} \times \frac{2}{3} = - 1$

$β = 5$

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If the straight line, 2x−3y+17=0 is perpendicular to the line passing through the points (7,17) and (15,β), then β equals :-

The correct option is C 5Slope of given line is 23Lines are perpendicular so17−β−8×23=−1β=5

If the straight line, $2 x - 3 y + 17 = 0$ is perpendicular to the line passing through the points $(7, 17)$ and $(15, β),$ then $β$ equals :-

The correct option is C $5$
Slope of given line is $\frac{2}{3}$

Lines are perpendicular so

$\frac{17 - β}{- 8} \times \frac{2}{3} = - 1$

$β = 5$