If the straight line, 2x−3y+17=0 is perpendicular to the line passing through the points (7,17) and (15,β) then β equals:
A
−5
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B
353
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C
5
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D
−353
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Solution
The correct option is C5 Slope of straight line. 2x−3y+17=0 is m1=23
Let slope of line passing through (7,17) and (15,β) be m2. ⇒m2=β−1715−7
Since, both the lines are perpendicular
So, m1.m2=−1 ⇒23.β−178=−1 ⇒β−17=−12 ⇒β=5