If the string of a conical pendulum makes an angle - with horizontal- then square of its time period is proportional to -1- sin- -2- cos- -3- tan- -4- cot-

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If the string...

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If the string of a conical pendulum makes an angle θ with horizontal, then square of its time period is proportional to (1) sinθ (2) cosθ (3) tanθ (4) cotθ

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45^{\circ}

t_{1}

60^{\circ}

t_{2}

\frac{t_{1}^{2}}{t_{2}^{2}}

45^{\circ}

t_{1}

60^{\circ}

t_{2}

\frac{t_{1}^{2}}{t_{2}^{2}}

θ

\to A = 2^i + 3^j + 5^k

cos θ = \frac{1}{2} a n d sin θ = \frac{\sqrt{3}}{2}

tan θ = \sqrt{3}

tan θ = \frac{sin θ}{cos θ}

0.1732 J

30 °

60 °

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