if the sum of first n terms of an AP is 2n^2-n+1, then find the tenth term of the AP

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Solution

Given Sn = 2n²-n+1

S1 = (2×1)-1+1= 2.

S2 = (2×2²)-2+1 = 7.

Therfore

First term, a1 = 2. &

Second term a2 = 8-2 = 5.

and

d = 5-2 =3 .

Now 10th term

An = a+(n-1)d

A10 = 2+(10-1)×3

= 2+27

= 29

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if the sum of first n terms of an AP is 2n^2-n+1, then find the tenth term of the AP

Given Sn = 2n²-n+1 S1 = (2×1)-1+1= 2. S2 = (2×2²)-2+1 = 7. Therfore First term, a1 = 2. & Second term a2 = 8-2 = 5. and d = 5-2 =3 . Now 10th term An = a+(n-1)d A10 = 2+(10-1)×3 = 2+27 = 29

Given Sn = 2n²-n+1

S1 = (2×1)-1+1= 2.

S2 = (2×2²)-2+1 = 7.

Therfore

First term, a1 = 2. &

Second term a2 = 8-2 = 5.

and

d = 5-2 =3 .

Now 10th term

An = a+(n-1)d

A10 = 2+(10-1)×3

= 2+27

= 29