If the sum of four consecutive odd numbers is $40$ , then the smallest number is

7

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9

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11

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13

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Solution

The correct option is A $7$
Let the first odd number be $x$ .
Thus, the other consecutive numbers are $x + 2, x + 4, x + 6$
Now, given that sum of all four numbers is 40,
$x + x + 2 + x + 4 + x + 6 = 40$
$\Rightarrow 4 x + 12 = 40$
$\Rightarrow 4 x = 28$
$\Rightarrow x = 7$
Thus, the smallest number $7$ .

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If the sum of four consecutive odd numbers is 40, then the smallest number is

The correct option is A 7Let the first odd number be x. Thus, the other consecutive numbers are x+2,x+4,x+6Now, given that sum of all four numbers is 40,x+x+2+x+4+x+6=40⇒4x+12=40⇒4x=28⇒x=7Thus, the smallest number 7.

If the sum of four consecutive odd numbers is $40$ , then the smallest number is