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Question

If the sum of n terms of an A.P. is ( pn + qn 2 ), where p and q are constants, find the common difference.

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Solution

The sum of n terms of an A.P. is ( pn+q n 2 ).

The formula for the sum of n terms in an A.P. is given by,

S n = n 2 [ 2a+( n1 )d ]

Substitute the value of S n as ( pn+q n 2 ) in the above expression.

pn+q n 2 = n 2 [ 2a+( n1 )d ] pn+q n 2 = n 2 [ 2a+ndd ] =na+ d 2 n 2 d 2 n pn+q n 2 =( a d 2 )n+ d 2 n 2

Compare the coefficients on both the sides.

d 2 =q d=2q

Thus, the common difference of the A.P. is 2q.


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