Question

If the sum of squares of two numbers whose sum is 22 is 404, then the product of the numbers is:

• A. 40
• B. 44
• C. 80
• D. 88
• E. 41

Answer 1

The correct option is A

40

Let the numbers be x and y. Then, $\left(x+y\right)$ = 22 and $x^2+y^2=404.$ Now, $2xy={\left(x+y\right)}^2-\left(x^2+y^2\right)={\left(22\right)}^2-404=484-404=80\Rightarrow xy=40.$