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Question

If the sum of the numbers 2A and 33 gives 5B, then find A and B. Given that number 2A is divisible by 10.
  1. A = 0, B = 0
  2. A = 0, B = 4
  3. A = 4, B = 0
  4. A = 0, B = 3


Solution

The correct option is D A = 0, B = 3
Since 2A is divisible by 10, number 2A should have 0 in its ones place. So, A = 0.
Now 2A becomes 20 and 20 + 33 = 53
Hence, 5B = 53 and B = 3

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