If the sum of the roots of the equation $a x^{2} + 2 x + 3 a = 0$ is equal to their product, then value of $a$ is:

$- \frac{2}{3}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$- 3$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$4$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$- \frac{1}{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$- \frac{2}{3}$

Explanation for the correct option.
In the given equation, $a x^{2} + 2 x + 3 a = 0$
Sum of roots $= - \frac{b}{a} = - \frac{2}{a}$ and product of roots $= \frac{c}{a} = \frac{3 a}{a} = 3$ .
As per the given information,
$\begin{array}{rcl} - \frac{2}{a} & = & 3 \\ \Rightarrow & a = - \frac{2}{3} \end{array}$
Hence, option A is correct.

Suggest Corrections

Similar questions

k x^{2} + 2 x + 3 x = 0

\frac{1}{3}

\frac{- 1}{3}

\frac{2}{3}

\frac{- 2}{3}

a x^{2} - 4 x + a^{2} = 0

a

If the sum of the roots of the equation $λ x^{2} + 2 x + 3 λ = 0$ be equal to their product $& λ \neq 0,$ then find the value of $λ .$

a x^{2} + b x + c = 0

k x^{2} + 2 x + 3 x = 0

\frac{1}{3}

\frac{- 1}{3}

\frac{2}{3}

\frac{- 2}{3}

Join BYJU'S Learning Program