Question

If the sum of the square of the distance of a point from the co-ordinates is $36$, then find its distance from the origin.

Answer 1

Let the point be $A(x,y)$

Given that $x^2+y^2=36$

Now, Distance of the point $A$ from origin $=\sqrt{{\left(x-0\right)}^2+{\left(y-0\right)}^2}$

$=\sqrt{x^2+y^2}$

$=\sqrt{36}$

$=6$ units