Question

If the sum of three consecutive multiples of 4 is 60, then the multiples are 16, 20, 24.

• A. 144, 148, 152
• B. 100, 104, 108

Answer 1

The correct option is A

144, 148, 152

Let $x$ be the multiple of $4$, then the next multiple is obtained by adding $4$ to $x$, i.e. $(x+4)$.

Likewise, $3^{rd}$ multiple is obtained by adding $4$ to $(x+4)$, i.e. $(x+8)$.

According to the question,

$x+(x+4)+(x+8)=60$

⇒ $(x+x+x)+12=60$ [Grouping like terms]

⇒ $3x=60-12=48$
⇒ $x=\frac{48}{3}$
⇒ $x=16$
So,
$x+4=16+4=20,$
$x+8=16+8=24$

Therefore, the multiples are $16,20,24.$