Let α,β,γ,δ are the roots and α+β=0
∴s1=α+β+γ+δ=−(−84)=2⇒γ+δ=2 ...(1)
s2=αβ+αγ+αδ+βγ+βδ+γδ=−134
⇒αβ+γ(α+β)+δ(α+β)+γδ=−134⇒αβ+γδ=−134 ...(2)
s3=αβγ+αβδ+αγδ+βγδ=−12
⇒(α+β)γδ+αβ(γ+δ)=−12⇒αβ(γ+δ)=−12
s4=αβγδ=34 ...(4)
Solving (1),(2),(3) and (4) we get
α=−12,β=12,γ=−1,δ=3