If the system of equations $a x + y = 3, x + 2 y = 3, 3 x + 4 y = 7$ is consistent, then value of $a$ is given by

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Solution

The correct option is B 2
The system of equations $a x + y = 3, x + 2 y = 3, 3 x + 4 y = 7$ is consistent.
solving $x + 2 y = 3$ and $3 x + 4 y = 7$ gives $x = 1$ and $y = 1$
$\Rightarrow a (1) + 1 = 3$
$∴ a = 2$
Hence, option A.

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