If the tangent and normal to a rectangular hyporbola xy=c2 at a point cuts off intercepts a1 and a2 on x−axis and b1, and b2 on the y−axis, then a1a2+b1b2=
A
c2
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B
0
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C
2c2
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D
2c2
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Solution
The correct option is B0 Let point P(x1,y1) on the hyperbola xy=c2
equations of tangents and normals at P on the hyperbola will be xy1+yx1=2c2 and xx1−yy1=x21−y21 respectively ⇒a1=2c2y1,b1=2c2x1,a2=x21−y21x1,b2=−(x21−y21)y1∴a1a2+b1b2=0