If the tangent and the normal to a rectangular hyperbola at a point cut off intercept a1,a2 on one axis and b1,b2 the other axis then a1a2+b1b2 is equal to:
A
−1
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B
0
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C
1
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D
√2
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Solution
The correct option is B0 Let the hyperbola be xy=c2 Tangent at any point (ct,ct) is x+yt2−2ct=0⇒x2ct+y2ct=1 ∴a1=2ct and b1=2ct Equation of normal is xt3−yt−ct4+c=0 ∴a2=c(t4−1)t3 and b2=−c(t4−1)t ∴a1a2+b1b2=0