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Question

If the tangent and the normal to a rectangular hyperbola at a point cut off intercept a1,a2 on one axis and b1,b2 the other axis then a1a2+b1b2 is equal to:

A
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B
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C
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D
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Solution

The correct option is B 0
Let the hyperbola be xy=c2
Tangent at any point (ct,ct) is
x+yt22ct=0x2ct+y2ct=1
a1=2ct and b1=2ct
Equation of normal is xt3ytct4+c=0
a2=c(t41)t3 and b2=c(t41)t
a1a2+b1b2=0

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