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Question

If the threshold frequency of a metal for photoelectric effect is v0, then which of the following will not happen?


A

If the frequency of the incident radiation is v0, the kinetic energy of the electrons ejected is zero.

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B

If the frequency of the incident radiation is v, the kinetic energy of the electrons ejected will be hv - hv0.

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C

If the frequency is kept sameat v but intensity is increased, the number of electrons ejected will increase.

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D

If the frequency of incident radiation is further increased, the number of photoelectrons ejected will increase.

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Solution

The correct option is D

If the frequency of incident radiation is further increased, the number of photoelectrons ejected will increase.


We will take all the options one by one for option (a), We know

KE = hν hν0

If hν = hν0 [or v = v0]

KE = 0

Option (a) is correct.

For option (b), we know from Einstein's equation,

KE=hνworkfunction

KE=hν hν0

It is also correct.

We know that, The number of electrons ejected is proportional to the intensity or brightness of light.

So option (c) is also correct.

The number of photoelectrons ejected only depends on intensity not on frequency. If the frequency is increased, Kinetic energy of photoelectrons ejected will increase.

Therefore option (d) is not correct.


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