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Question

# If the threshold frequency of a metal for photoelectric effect is v0, then which of the following will not happen?

A

If the frequency of the incident radiation is v0, the kinetic energy of the electrons ejected is zero.

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B

If the frequency of the incident radiation is v, the kinetic energy of the electrons ejected will be hv - hv0.

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C

If the frequency is kept sameat v but intensity is increased, the number of electrons ejected will increase.

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D

If the frequency of incident radiation is further increased, the number of photoelectrons ejected will increase.

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Solution

## The correct option is D If the frequency of incident radiation is further increased, the number of photoelectrons ejected will increase. We will take all the options one by one for option (a), We know KE = hν − hν0 If hν = hν0 [or v = v0] KE = 0 Option (a) is correct. For option (b), we know from Einstein's equation, KE=hν−workfunction KE=hν − hν0 It is also correct. ⇒ We know that, The number of electrons ejected is proportional to the intensity or brightness of light. So option (c) is also correct. ⇒ The number of photoelectrons ejected only depends on intensity not on frequency. If the frequency is increased, Kinetic energy of photoelectrons ejected will increase. Therefore option (d) is not correct.

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