If the threshold wavelength (λ∘) for the ejection of electrons from a metal is 330nm, then the work function for the photoelectric emission is:
A
6×10−10J
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B
4×10−18J
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C
9×10−19J
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D
6×10−19J
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Solution
The correct option is D6×10−19J Work function (W)=hν0 = hcλ0 Where; ν0=Threshold frequency λ0=Threshold wavelength W=(6.626×10−34Js)(3×108ms−1)(330×10−9m) W=6×10−19J