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Question

If the time of flight of a bullet over a horizontal range R is T, then inclination of the direction of projection with the horizontal is

A
tan1[gT22R]
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B
tan1[2R2gT]
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C
tan1[2Rg2π]
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D
tan1[2RgT]
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Solution

The correct option is A tan1[gT22R]
Time of flight, T=2vsinθg
T2=4v2sin2θg2 ......(i)
We know that,
Range,R=v2(2sinθcosθ)g ......(ii)
Dividing (i) from (ii), we get
T2R=2gtanθ
tanθ=gT22R
θ=tan1[gT22R]

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