MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Introducing Flux

If the total ...

Question

If the total electric flux through the paraboloidal surface due to a uniform electric field of magnitude $E_{0}$ in the direction shown in fig is $ϕ = X E_{0} π r^{2} / 2$ . Find out the value of X?

Open in App

Solution

total field lines entering the flat surface= total field lines leaving the curved surface
Therefore, flux = field perpendicular to flat surface $\times$ Area of flat surface = $E_{0} π r^{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. If the constant electric field in the figure has a magnitude

E_{0}

, calculate the total electric flux through the paraboloidal surface.

Q. A ring of diameter d is rotated in a uniform electric field until be position of maximum electric flux is found. The flux is found to be

ϕ

. If the electric field strength is

E = \frac{X ϕ}{π d^{2}}

Q. The cube as shown in Fig. has sides of length

L = 10.0 c m

. The electric field is uniform, has a magnitude

E = 4.00 \times 10^{3} N C^{- 1}

, and is parallel to the

x y - p l a n e

37^{\circ}

measured from the

+ x - a x i s

+ y - a x i s

.
Electric flux passing through surface

S_{6}

Q. The electric flux

ϕ

through a hemispherical surface of radius R, placed in a uniform electric field of intensity E parallel to the axis of its circular plane is :

Q. A Gaussian surface in the cylinder of cross section

π a^{2}

L

is immersed in a uniform electric field

¯ ¯¯ ¯ E

with the cylinder axis parallel to the field. The flux

^{'} ϕ^{'}

of the electric field through the closed surface is:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Electric Flux

PHYSICS

Watch in App

explore_more_icon

Explore more

Introducing Flux

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon