If the total hardness and alkalinity of a sample of water are 300 mg/L and 100 mg/L $(C a C O_{3} s c a l e)$ respectively, then its carbonate and non-carbonate hardness (in units of mg/L) will be respectively

100 and 200

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400 and zero

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400 and 300

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100 and 400

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Solution

The correct option is A 100 and 200
(a) Carbonate hardness is equal to total hardness or alkalinity, whichever is less i.e. 100 mg/L

Non-carbonate hardness

= Total hardness - Alkalinity

= 300 - 100

= 200 mg/L

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Similar questions

C a C O_{3}

C a C O_{3}

[N a^{+}] = 38 m g / l, ∣ ∣ C a^{2_{+}} ∣ ∣ = 10 m g / l

[H C O_{3}^{-}] = 183 m g / l, [M g^{2 +}] = 12 m g / l

[C O_{3}^{2 -}] = 30 m g / l, [A l^{3 +}] = 27 m g / l

[S O_{4}^{2 -}] = 45 m g / l

(i n m g / l a s C a C O_{3})

C a C O_{3}

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