wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

If the total number of electrons present in a pure sample of FeSO4.7H2O is 4.336×1026
then the total number of moles of oxygen atoms present in FeSO4.7H2O:


Open in App
Solution

The total number of electrons in one formula unit of FeSO4.7H2O
=(26+16+4×8+14×1+7×8)=144

So, 144×6.022×1023 electrons are present in 1 mole of FeSO4.7H2O.

Hence, 4.336×1026 electrons will be present in
=4.336×10261.44×6.022×1023 moles of FeSO4.7H2O

=5 moles of FeSO4.7H2O

From the formula unit :
1 mole of FeSO4.7H2O contains 11 moles of O atoms.

Thus, 5 moles of FeSO4.7H2O will contains 55 moles of O atoms.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mole Concept
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon