If the total vapour pressure of liquid mixture a and b is given by the equation P = 160 X + 80 then the ratio of vapour pressure of pure liquid a and b is given by

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What will be the vapour pressure of pure components A and B respectively if vapour pressure of mixture of these two liquids is given by Pt=100+250Xb torr

Q. Mole fraction of component

A

in the vapour phase is

X_{1}

and mole fraction of component

A

in liquid mixture is

X_{2} (P_{A}^{o} =

vapour pressure of pure

A; P_{B}^{o} =

vapour pressure of pure B) then total vapour pressure of the liquid mixture is:

Q. The mole fraction of component A in vapour phase is

x_{1}

and mole fraction of component A in liquid mixture is

x_{2}

(P_{A}^{0} =

vapour pressure of pure A,

P_{B}^{0} =

vapour pressure of pure B). Then total vapour pressure of the liquid mixture is:-

Q. The mole fraction of component A in the vapour phase is

χ_{1}

and mole fraction of component A in liquid mixture is

χ_{2}

(

P_{A}^{o}

= vapour pressure of pure A;

P_{B}^{o}

= vapour pressure of pure B). Then the total vapour pressure of the liquid mixture is:

Q. At a given temperature, the vapour pressure in mm of Hg of a solution of two volatile liquids A & B is given by the equation:

P = 120 - 80 X_{B}

(Where

X_{B}

is molefraction of B)

Vapour pressures of pure A & B at the same temperature are respectively:

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