If the two polynomials x2−11x+a and x2−14x+2a have a common factor, then a=
Exprssions x2−11x+a and x2−14x+2a will have a common factor, then
⇒x2−22a+14a=xa−2a=1−14+11
⇒x2−8a=x−a=1−3
⇒x2=8a3 & x=a3
⇒(a3)2=8a3⇒a29=8a3
⇒a=0,24.
Alternate Method : We can check by putting the values of a from the options.