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Question

If the two polynomials x211x+a and x214x+2a have a common factor, then a=

A
0
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B
24
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C
0,3
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D
0,24
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Solution

The correct option is D 0,24

Exprssions x211x+a and x214x+2a will have a common factor, then
x222a+14a=xa2a=114+11

x28a=xa=13
x2=8a3 & x=a3

(a3)2=8a3a29=8a3
a=0,24.

Alternate Method : We can check by putting the values of a from the options.


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