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Question

If the value of a3+b3+c3-3abc = 10k, then find the value of k, when a = 249, b = 250 and c = 251.


A

225

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B

2250

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C

250

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D

2500

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E

None of these

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Solution

The correct option is A

225


a3+b3+c3-3abc = 0.5(a+b+c)[(a-b)2 + (b-c)2 + (c-a)2​] = 0.5 x 750 x 6 = 2250

Now, 10k = 2250 k = 225


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