Question

If the value of C.F.S.E. for "Ni" is ${\Delta }_0$ then it is for Pd should be ?

• A. $1.1{\Delta }_0$
• B. $0.5{\Delta }_0$
• C. $1.5{\Delta }_0$
• D. none of the above

Answer 1

Answer: (C)

$1.5{\Delta }_0$

Ongoing from $3d$ to $4d$ series C.F.S.E increases by $50\%$

Now, for $Ni$ CFSE $={△}_o$

$\Rightarrow$ For $P_t={△}_o+\frac{50}{100}{△}_o$

$=1.5{△}_o$