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Question

If the value of determinant ∣ ∣a111b111c∣ ∣ is positive then

A
abc>11
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B
abc<8
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C
abc>8
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D
None of these
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Solution

The correct option is C abc>8
Δ=∣ ∣a111b111c∣ ∣=abc(a+b+c)+2 As Δ>0abc+2>a+b+c ...(A)Using A. M. >G.M.

a+b+c3>(abc)1/3or a+b+c>3(abc)1/3 ...(B)By (A) and (B) we haveabc+2>a+b+c>3(abc)1/3

abc+2>3(abc)1/3

2+x3>3x(x=(abc)1/3)

x33x+2>0

(x1)2(x+2)>0x>2

(abc)1/3>2

abc>8

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