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Byju's Answer
Standard VIII
Chemistry
Tests for Hydrogen
If the value ...
Question
If the value of
E
n
=
78.4 kcal/mole, then the order of the orbit in hydrogen atom is:
A
2
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B
3
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C
4
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D
1
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Solution
The correct option is
A
2
E
n
=
78.4 kcal/mole =>
78.4
×
4.2
=
329.28 kJ/mole
=
−
329.28
96.5
eV
=
3.4 eV, which is the energy of 2nd orbit of Hydrogen atom.
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